the sum of two consecutive multiples of 7 is 161 find these multiples
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Let the first no. be 7a
Second No. = 7a +7
According to question
7a +7a +7 = 161
=> 14 a = 154
=> a = 11
Required numbers are 77 and 84
Hope it will help you
Please mark as brainliest if you liked the solution
Second No. = 7a +7
According to question
7a +7a +7 = 161
=> 14 a = 154
=> a = 11
Required numbers are 77 and 84
Hope it will help you
Please mark as brainliest if you liked the solution
shaiq:
nice friend
not done in steps
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0
Answer:
solution let first multiple equal 7x second multiple 7 x +
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