the sum of two consecutive multiples of 7 is 161. find these multiples
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let,the two consecutive multiples of 7 are 7(x) and 7(x+1)
7(x)+7(x+1)=161
7x+7x+7=161
14x=161-7
14x=154
x=154/14
x=11
the two consecutive multiples are 7x11=77 and 7x12=84
77+84=161
7(x)+7(x+1)=161
7x+7x+7=161
14x=161-7
14x=154
x=154/14
x=11
the two consecutive multiples are 7x11=77 and 7x12=84
77+84=161
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