Question

The sum of two digit number and the number formed by reversing the order of digit is 66

Answer 1

Step-by-step explanation:

Assuming you need the sum of the digit of the original number

let the 2digit number be 10x + y

therefore number formed by reversing the digits is 10y + X

as per question

10x + y + 10 y + X = 11 X + 11 y = 66 (given)

therefore 11(X+y)=66

therefore X+y =11

there fore the sum of the two digits is 11

however the number itself cannot be found..