Question

the sum of two digit number and the number formed by reversing the digit is 110 if the 10 is subtracted from the number the new number is 4 more than 5 times the sum of digits find the number ​

Answer 1

Answer:

hey dude ans.. is here

Step-by-step explanation:

let the unit digit be y & tens digit be x

original no.=(10x+y)

After interchanging the digits.

New no .=(10y+x)

(10x+y)+(10y+x)=110

11x+11y=110

11(x+y)=110

x+y=110/11

x+y=10

x+y=10.........(1)

x=10-y..........(2)

(10x+y)-10=4+5(x+y)

(10x+y)-10=4+5(10)

(10x+y)=4+50+10

(10x+y)=64

10(10-y)+y=64

100-10y+y=64

100-9y=64

-9y=64-100

-9y=-36

y=36/9

=4

put this value in eq...(2)

x=10-y

x=10-4

=6

HENCE FIRST NO.IS 6 & SECOND NO. IS 4

Original no. is 10x+y

=10*6+4

=66+4

=64...

HOPE IT HELPS U DEAR PLZ MARK IT AS BRAINLIEST....

Answer 2

Answer:

hey

Step-by-step explanation:

I'll come to ur quess