The sum of two digit number and the number formed by interchanging it's digit is 110. if 10 is subtracted from the original number. the new number is 4 more than 5 times the sum of the digit of the original number find the original number
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13
Answer:
64
Step-by-step explanation:
Let say number = 10x+y
Interchanged number = 10y+x
Sum = 11x +11y = 110
x +y = 10
10x+y-10 = 4 + 5×(x+y)
10x +y -14 = 5x +5y
5x -4y = 14
4x+4y = 40
9x = 54
x = 6
6+y = 10
y = 4
Number = 64
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