the sum of two digit number and the number obtained by interchanging the digits of the number is 121. if the digits of a number differ by 3, find the number.
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Let the two digit number be 10x+y and the number obtained by interchanging the digits is 10y+x.
Given that the sum of a two digit number and the number obtained by interchanging is 121.
10x+y+10y+x=121
11(x+y)=121
x+y=11-->1
the difference between their digits is 3⇒x-y=3 -->2
on solving the above equations, x=7 and y=4
Step-by-step explanation:
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