Question

the sum of two digit number and the number obtained by interchanging the digits is 99 if the digit at tens place exceeds the digit at unit place by 3 find the number​

Answer 1

Answer:

Step-by-step explanation:

Let x be the number at units place and y be the number at tens place

Two digit number=10y + x

According to the conditions,

y=2x

2x-y=0..(1)

10x + y + 10y + x=99

11x + 11y=99

11(x + y)=99

x + y=99/11

x + y=9..(2)

Solving (1) and (2),we get

2x-y=0

x+y=9

3x=9

x=9/3

x=3

Putting x=3 in (1)

2x-y=0

2(3)-y=0

6-y=0

y=6

∴The two digit number=10y + x=10(6) + 3=63

∴The number is 63