Question

the sum of two digit number and the number obtained by reversing the order of its digit is 121, and the two digits differ by 3 find the number

Answer 1

Let no at ones= x 
Let no. at tens=10(x+3)
                       =10x+ 30
New no.
Let no. at ones place x+3
let no. ta tens place 10x
10x +30+x + 10x + x +3= 121
22x=88
x=88/22
x=4
the original no. is 74
the new no. is 47

Hope it helps :) 

Answer 2

Answer:

hope this ans. is ryt.......