Math, asked by Bhawanikumawat, 1 year ago

the sum of two digit number and the number obtained by reversing tbe order of its digits is 165.if the digits differ by 3,find the number.

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Answered by rahulduhan059p3k9uv
3

student-name Smiley asked in Math
the sum of a 2 digit number and the number obtained by reversing the order of its digits is 165.if the digits differ by 3,find the number

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student-name Palak Harwani answered this
22 helpful votes in Math, Class X
Let 1 digit be y.

:. Other digit will be y - 3

So, the no. is 10y + y - 3 = 11y-3

By reversing the digits the no. becomes 10(y - 3) + y = 11y - 30.

Sum of the 2 nos. = 165

11y - 3 + 11y - 30 = 165

22y - 33 = 165

22y = 198

y = 9

So, the no. is 96.

Since the digits differ by 3, they could be y and y +3.

So, the no. becomes 10y + y + 3 = 11y + 3

By reversing the digits, it becomes 10(y + 3) + y = 11y + 30

Therefore, 11y + 3 + 11y +30 = 165

22y +33 = 165

22y = 132

y = 6

Therefore the no. is 69

Hope it helps
Answered by ydharmendra888
1
I think it is right answer
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