the sum of two digit number and the number obtained by reversing tbe order of its digits is 165.if the digits differ by 3,find the number.
Answers
Answered by
3
student-name Smiley asked in Math
the sum of a 2 digit number and the number obtained by reversing the order of its digits is 165.if the digits differ by 3,find the number
Share 11 Follow 0
student-name Palak Harwani answered this
22 helpful votes in Math, Class X
Let 1 digit be y.
:. Other digit will be y - 3
So, the no. is 10y + y - 3 = 11y-3
By reversing the digits the no. becomes 10(y - 3) + y = 11y - 30.
Sum of the 2 nos. = 165
11y - 3 + 11y - 30 = 165
22y - 33 = 165
22y = 198
y = 9
So, the no. is 96.
Since the digits differ by 3, they could be y and y +3.
So, the no. becomes 10y + y + 3 = 11y + 3
By reversing the digits, it becomes 10(y + 3) + y = 11y + 30
Therefore, 11y + 3 + 11y +30 = 165
22y +33 = 165
22y = 132
y = 6
Therefore the no. is 69
Hope it helps
Answered by
1
I think it is right answer
Attachments:
Similar questions