Question

the sum of two digit number and the number obtained by reversing the order of digit is 121 if the number differ by 3 find the number

Answer 1

let two digit number be 10x + y
sum of two digit number and number obtained by reversing the order of digit is 121 if the number differ by 3, so x - y = 3 or x = y + 3
10x + y + 10y + x = 121
11x + 11y = 121
11(x + y) = 121
x + y = 11
y + 3 + y = 11
2y = 11 - 3
2y = 8
y = 4
so x = y + 3 = 4 + 3 = 7
the two digit number is 10x + y = 10*7 + 3 = 73