The sum of two digit number and the number obtained by reversing the digit is 66.if the digits of the number differ by 2,find the number
Answers
Answered by
14
10x+y+10y+x=66
11x+11y=66
X+y=6
X-y=2
By solve we get x=4 y=2
So number is 42
Answered by
3
10x +y +10y+x=66
11x+11y=66
x+y=6
and given that x-y=2
now by solving
x=4 & y=2
thus the number is 10x+y =10×4+2
=40+2
=42
so answer is 42.
11x+11y=66
x+y=6
and given that x-y=2
now by solving
x=4 & y=2
thus the number is 10x+y =10×4+2
=40+2
=42
so answer is 42.
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