Math, asked by cutecrystal889, 1 year ago

The sum of two digit number and the number obtained by reversing the order of its digit is 88. the number of such numbers in which the tens digit is greater than the unit digit is ?

Answers

Answered by omsharma050322

1

I think number are
71 ,62 , 53

cutecrystal889: can you solve it ?

omsharma050322: yes

cutecrystal889: please share it if it's possible for you

omsharma050322: 71+17=88,62+26=88,53+35=88

omsharma050322: if you need more help than ask me for it

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