The sum of two digit number and the number obtained by reversing the order of its digits is 88. Express this is form of linear equation
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10x+y+10y+x=88
11x+11y=88
11(x+y)=88
x+y=88/11
x+y=8.
here is your answer hope it will help you
11x+11y=88
11(x+y)=88
x+y=88/11
x+y=8.
here is your answer hope it will help you
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