Question

the sum of two digit number and the number obtained by reversing the digits is 66 if the digits of the number differ by 2 find the number . how many such numbers are there ?​

Answer 1

Let the digit on the ones place be y

And the digit on the tens place be x

Then, number = 10x + y

Number obtained by reversing the digits = 10y + x

CASE 1

10x + y + 10y + x = 66

11x + 11y = 66

x + y = 6 -------(1)

CASE 2

x - y = 2 -------(2)

Solve (1) and (2), we get

x = 4, y = 2

Number = 42

Also, if y - x = 2

then, y = 4 and x = 2

So number in this case = 24.

Two such numbers are possible, i.e. 42 and 24.

Answer 2

Answer:here is your answers pic.

Step-by-step explanation: