Question

the sum of two digit number is 15 if the number formed by reversing the digit is less than the original number by 27 find the original number

Answer 1

hey mate here is your answer

let tens digit of the original number be x

so original number,

10(x) + (15-x) 

reversing digits mean

10(15-x) + x

therefore

[10(x) + (15-x)]-[10(15-x)+x] = 27

or  10x + 15-x - 150+10x-x = 27

or 10x + 10x + 15 - 150 -x - x = 27

or 20x - 135 -2x = 27

or 18x - 135 = 27

or 18x = 27 + 135

or 18x = 162

or x = 162/18

or x = 9

original number = 10(x) + (15-x) 

                             = 10(9) + (15-9)

                           = 90

                              =96

mark it as brainliests

Answer 2

Let the digits be x and y

Given, x + y = 15

So if we have to write two digit number we write,
10x + y

Now if we reverse the digits it will become
10y + x

Given,

10x + y -( 10y + x) = 27

=> 10x + y - 10y - x = 27

=> 9x - 9y = 27

=> 9(x - y) = 27

=> x - y = 27/9

=> $\textbf{ x \: - \:y = \: 3 }$


Now we know that x + y = 15

and x - y = 3

adding both equation we get

x + y + x - y = 15 + 3

=> 2x = 18

=> X = 18/2

=> x = 9


Putting value of x in first equation we get

x + y = 15

=> 9 + y = 15

=> y = 15 - 9

=> y = 6


So digit is 10x + y

=> 10(9) + 6

=> 96


Your answer :- $\bold{96}$


Hope it helps dear friend ☺️✌️