The sum of two digit number is 17. If the number formed by reversing the digits is less than the original number by 9,find the original number.
Answers
Answer:
★FIND:
the original number = ?
★GIVEN,
The sum of two digit number is 17.
If the number formed by reversing the digits is less than the original number by 9.
★SOLUTION:
The sum of two digit number is 17
➡️8+9=17
➡️9+8=17
So the 8+9=17 is correct.
if we reverse 89 then we get 98.
Subtract 9 from the reversed number 98
=>98-9
=>89
The original number is 98.
- we need to find the original number
- Sum of digits of a two digit number = 17
- number formed by reversing the digits is less than the original number by 9.
- Let units place digit be x
- Let ten's place digit be y
↠ Number formed = 10x + y
Sum of digits of a two digit number = 17.
- x + y = 17
- x = 17 - y .....1)
Number formed by reversing the digits is less than the original number by 9.
- Original number = 10x + y
- Number formed on revercing the digits is 10y + x.
⇢ 10x + y -(10y + x) = 9
⇢ 10x + y - 10y - x = 9
⇢ 9x - 9y = 9
- Dividing both sides by 9
⇢ x - y = 1
- From equation 1)
⇢ 17 - y - y = 1
⇢ -2y = 1 - 17
⇢ - 2y = -16
⇢ y = 8
- Substituting value of y in Equation ..1)
↠ x = 17 - y
↠ x = 17 - 8
↠ x = 9
So,
- Original number 10x + y
= 10 × 9 + 8
= 90 + 8
= 98
- Number formed on revercing the digits is 10 y + x
= 10 × 8 + 9
= 80 + 9
= 89
Hence,
- Original number = 98
✫Verification :-
Sum of digits of a two digit number = 17.
So,
= x + y = 17
= 8 + 9 = 17
= 17 = 17
LHS = RHS
Hence, verified
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