Question

The sum of two digit number is 7 if the digit is reversed the new number increased by 3 equals to 4 times the original no. Find the original no.

Answer 1

Let the number be 10X + Y

X + Y = 7 - eq. 1

Given :

10Y + X + 3 = 4 (10X + Y)

10Y + X + 3 = 40X + 4Y

40X + 4Y - 10Y - X = 3

39X - 6Y = 3

Divide the equation by 3

13X - 2Y = 1 - eq. 2

Multiply eq. 1 by 2

2X + 2Y = 14
13X - 2Y = 1
___________
15X = 15

X = 15/15 = 1

X + Y = 7

1 + Y = 7

Y = 7 - 1

Y = 6

Thus,

The no. = 16

Hope it helps :)

Answer 2

HEY Buddy....!! here is ur answer

Answer : 16

Let, the digits of number are x and y

Then according to the question :

x+y = 7.....(1)

And (10y+x) +3 = 4(10x+y)

=> 39x–6y = 3...(2)

From equation (1) and (2)

x+y = 7....(1)

39x–6y = 3...(2)

On Multiplying by 39 in equation (1)

39x+39y = 273...(3)

On subtracting equation (2) from (3)

45y = 270

y = 6

On putting the value of y in equation (1)

x = 1

Number = 10x+y = 10×1+6 = 16

So, the original number will be 16

I hope it will be helpful for you...!!

THANK YOU ✌️✌️