Question

the sum of two digit number is 9 if the digit are reversed, the number formed bears the ratio 3 :8 to the original number .find the original number.
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Answer 1

Answer:

27

Step-by-step explanation:

Let the required number be 10x+y.

Solution:

x+y=9 take this as eq1.

In Next step we have to reverse the digits.

Also, 10x+y/10y+x=3/8

= 3/8 as given in question.

So, 80x+8y=30y+3x

77x=22y

77x=22(9-x) this is from eq1.

77x=198-22x

77x+22x=198

99x=198

x=198÷99

Cancel with 99.

x=2.

From eq1, y=7.

So, number =10(2)+7

Therefore, Number =27.