Question

the sum of two digit number is 9 the number is 6 times the unit. find the number

Answer 1

$\underline{\textsf{Given:}}$

$\textsf{Sum of the digits is 9 and the number is 6 times unit digit}$

$\underline{\textsf{To find:}}$

$\textsf{The number}$

$\underline{\textsf{Solution:}}$

$\textsf{Let the two digit number be 10x+y}$

$\textsf{As per given data,}$

$\mathsf{x+y=9}$......(1)

$\mathsf{10x+y=6y}$

$\mathsf{10x=5y}$......(2)

$\textsf{Using (1) in (2)}$

$\mathsf{10x=5(9-x)}$

$\mathsf{10x=45-5x}$

$\mathsf{10x+5x=45}$

$\mathsf{15x=45}$

$\mathsf{x=\dfrac{45}{15}}$

$\mathsf{x=3}$

$\textsf{Put x=3 in (1) we get}$

$\mathsf{3+y=9}$

$\implies\mathsf{y=6}$

$\therefore\textsf{The required number is}$

$\mathsf{10x+y=10(3)+6=30+6=36}$

$\underline{\textsf{Answer:}}$

$\mathsf{36}$

$\underline{\textsf{Find more:}}$

The sum of the digits of a two-digit number is 14, The number is nineteen times the

digit at its ones place. Find the number.

https://brainly.in/question/23398127

Answer 2

Given:

Sum of the digits is 9 and the number is 6 times unit digit

To find:

The number

Solution:

Let the two digit number be 10x+y

As per given data,

x+y=9 ......(1)

10x+y=6y

10x=5y ......(2)

Using (1) in (2)

10x=5(9−x)

10x=45−5x

10x+5x=45

15x=45

x= 15/45

x=3

Put x=3 in (1) we get

3+y=9

⟹y=6

∴The required number is

10x+y=10(3)+6=30+6=36

$\huge\green {\boxed{36 }}$