The sum of two digit number is eight and the difference between a number and formed by the reversing the digit is 18 find the number?
Answers
Answer:
Step-by-step explanation:
The sum of digits of a two digit number is 8 and the difference between the number and that formed by reversing the digit is 18. What is the number?
Let us assume the digits of a number as 'x' and 'y'. Since it is a 2 digit number, we have one's place and ten's place. ( i.e., The place value of one digit is multiple of 10 and the place value of other digit is one.) I assume you know the difference between place value and face value.
Now going to the problem,
Sum of two digits is 8. => x +y=8→A
Diff between number and its reverse:
=> (10x+y)-(10y+x)=18
=>9x-9y=18
=> x-y=(18/9)=2→B
Solving A and B
x+y=8
x-y=2
=>2x=10=>x=5. Hence y = 3.
Hence the required number is 53
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Answer:
35
Step-by-step explanation:
2 digit number is of tens and ones digit.....
tens digit +ones digit=8
according to the above equation, we can say that
let ones digit be x and tens digit will be 8-x.
the 2 digit number will be 10(8-x)+x......we multiplied 10 because 8-x is a tens digit. the number is 80-10x+x= 80-9x
reversed number will be 10x+ 8-x= 9x+8
ATQ,
80-9x-(9x+8)= 18
80-9x-9x-8=18
72-18x=18
-18x=18-72
-18x=(-54)
18x=54
x=3
the required number is 35 or 53....
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