Question

The sum of two digit number obtained by reversing the order of the digits is 165.If the digits differ by 3,find the number ,when tens digits is bigger than the units digit ​

Answer 1

Answer:

96

Step-by-step explanation:

given,

tens digit > units digit

difference = 3

sum = 165

165 is a big number so, mostly in 90 series

not below 93 because difference is of 3

so if 9 is tens digit then 9-3 = 6 is units digit

answer = 96

hope this will help you

Answer 2

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Let the  No. Be xy 

ATQ, 

xy + yx               = 165 

10x + y + 10y+x = 165

11x + 11y           =  165

Divide Both sides By 11 

         x + y          =  15 __________(1)

Also,x - y           = 3 ____________(2) 

By 1 and 2 we get 

2x = 18 

x   =  9 

y   =  6

So the number is 96 or 69

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