Question

The sum of two even consecutive integers is 46 find the intergers

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :- }}}}$

One number is 22 and second number is 24.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

$\textbf{Given : }$

The numbers are even and consecutive

Sum is 46

$\textbf{To find :}$

The numbers

$\textbf{Solution :}$

Consider one number as x

Consider the second number as x + 2

★ Equation :

$\boxed{\tt{x + (x + 2) = 46}}$

$\tt{\implies} \: x + x + 2 = 46$

$\tt{\implies} \: 2x + 2 = 46$

$\tt{\implies} \: 2x = 46 - 2$

$\tt{\implies} \: 2x = 44$

$\tt{\implies} \: x = \dfrac{44}{2}$

$\tt{\implies} \: x = 22$

One number = 22

Value of x + 2

$\tt{\implies} \: 22 + 4$

$\tt{\implies} \: 24$

$\therefore$ One number is 22 and second number is 24.

$\mathfrak{\large{\underline{\underline{Verification :-}}}}$

$\tt{\implies} \: 22 + 24$

$\tt{\implies} \: 46$

$\therefore$ One number is 22 and second number is 24.

Answer 2

Answer:

First number = 22

Second number = 24

Step-by-step explanation:

Let the first number = x

Let the second number = x + 2

According to the question ,

The sum of two even consecutive ingers = 46.

so,

x +  x + 2  = 46

2x + 2 = 46

2x = 46 - 2

2x = 44

x = 44 / 2

x = 22

∴ FIRST NUMBER = X

                              = 22

  SECOND NUMBER = X + 2

                                   = 22 + 2

                                   = 24.

PLS MARK AS BRAINLIST AND PLS FOLLOW ME.