The sum of two forces acting at a point is 16 N. If the resultant
force is 8 N and its direction is perpendicular to minimum
force then the forces are
(a)6 N and 10 N
(b)8 N and 8 N
(c)4 N and 12 N
(d)2 N and 14 N
Answers
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Answer:
F2+64=(16-F)2
On solving F=OTHER F=10
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Explanation:
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