The sum of two forces acting at a point is 16 N. If
the resultant force is 8 N and its direction is
perpendicular to minimum force then the forces are
(A) 6 N and 10 N
(B) 8 N and 8 N
(C) 4 N and 12 N
(D) 2 N and 14 N
DA DO CD & DA
.
Answers
Answered by
0
Explanation:
A+B=16...(1)
tanα=
A+Bcosθ
Bsinθ
=tan90
Thus, A+Bcosθ=0⇒cosθ=−
B
A
...(2)
We also have: 8=
A
2
+B
2
+2ABcosθ
...(3)
Solving these we get, A=6N and B=10N
Answered By
MADHUR GUPTA
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