Question

The sum of two forces acting at a point is 16 N. If
the resultant force is 8 N and its direction is
perpendicular to minimum force then the forces are
(A) 6 N and 10 N
(B) 8 N and 8 N
(C) 4 N and 12 N
(D) 2 N and 14 N
DA DO CD & DA
.​

Answer 1

Explanation:

A+B=16...(1)

tanα=

A+Bcosθ

Bsinθ

=tan90

Thus, A+Bcosθ=0⇒cosθ=−

B

A

...(2)

We also have: 8=

A

2

+B

2

+2ABcosθ

...(3)

Solving these we get, A=6N and B=10N

Answered By

MADHUR GUPTA