The sum of two forces acting at a point is 16 newton is resultant force is 8 newton and its direction perpendicular to the minimum force then the forces
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Since resultant force is perpendicular to smaller force let smaller force be b and bigger force be a. Now we know that a b s ( a ) + a b s ( b ) ...
Let y+x=16n (sum of two forces) r=8n ( resultant of forces) suppose x<y then, ... the resultant force is 8 Newton and its direction is perpendicular to minimum force then the forces are?
Let y+x=16n (sum of two forces) r=8n ( resultant of forces) suppose x<y then, ... the resultant force is 8 Newton and its direction is perpendicular to minimum force then the forces are?
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