The sum of two forces acting at a point is 16n the resultant force is 8 n find the forces
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Answer:
Let the smaller of the two forces is of magnitude be
F
N.
Hence the larger one will be
(
16
−
F
)
N. As the resultant
8
N is perpendicular to
F
we can write.
F
2
+
8
2
=
(
16
−
F
)
2
⇒
(
16
−
F
)
2
−
F
2
=
64
⇒
16
(
16
−
2
F
)
=
64
⇒
256
−
32
F
=
64
⇒
F
=
256
−
64
32
=
6
N
So the smaller force is
6
N
and the larger force is
10 N
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