Question

The sum of two forces acting at a point is 16n the resultant force is 8 n find the forces

Answer 1

Answer:

Let the smaller of the two forces is of magnitude be

F

N.

Hence the larger one will be

(

16

−

F

)

N. As the resultant

8

N is perpendicular to

F

we can write.

F

2

+

8

2

=

(

16

−

F

)

2

⇒

(

16

−

F

)

2

−

F

2

=

64

⇒

16

(

16

−

2

F

)

=

64

⇒

256

−

32

F

=

64

⇒

F

=

256

−

64

32

=

6

N

So the smaller force is

6

N

and the larger force is

10 N