Question

the sum of two fractions is three times their difference . Six times the smaller fraction exceeds the larger fraction by 3/2.Find the fractions

Answer 1

Six times the smaller fraction exceeds the larger fraction by 1 1/2

Let x ,(6x- 3/2)represent the smaller and larger fraction respectively

Questions States***

x +(6x- 3/2) = 3[(x -(6x- 3/2)]

solcing for x

7x - 3/2 = 3x - 3(6x-3/2)

7x - 3/2 = 3x - 18x + 9/2

22x = 12/2

x = 12/44 = 3/11, smaller of the fractions.

Larger is = (18/11 - 3/2) = (36-33)/22 = 3/22