Question

The sum of two integer is-16.if one of them is 53, find the other​

Answer 1

Step-by-step explanation:

Let the other number be x

A/q,

x+ 53 = (-16)

=> x= -16-53

=>x = ((-69))

So the number is (-69)(ans)

Answer 2

Given : ↴

$\sf \: The \: sum \: of \: two \: integer \: is \: -16$

$\sf \: One \: of \: the \: number \: is \: 53$

To Find : ↴

$\sf \: We \: have \: to \: find \: the \: another \: number.$

So, Let's Start : ↴

$\sf \: Let \: the \: another \: number \: be \: x.$

$\sf \longrightarrow \: 53 \: + \: x \: = \: -16$

$\sf \longrightarrow \: \: x \: = \: \: - \: 16 \: - \: 53$

$\sf \longrightarrow \: \: x \: = \: \: - \: 69$

$\sf \: So, \: the \: another \: number \: is -69$

________________________

$\sf \: Let's \: Verify \: Our \: Answer \:$ ↴

$\sf \longrightarrow \: -16\: = \:+53\: -69$

$\sf \: Hence, \: Our \: Answer \: is \: correct.$

________________________

$\sf \: Rules\: Used\: to\: solve \:this\: question\: are\:$ ↴

$\boxed{\begin{array} {c|c} \sf{ +,- } & \sf{ - } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{- , +} & \sf{ - } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{+,+} & \sf{ + } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad }{} \\ \sf{-,-} & \sf{ + }\end{array}}$

$\sf \: Some\: More\: Information\: about\: Integers\: :$ ↴

$\sf \: Integers\: is\:a\:Latin\: word,\: which \:means\: Whole.$

$\sf \:Integer, \: Whole\:-\: valued\:positive\:or\:negative \:number \:or \:0$

$\sf \:Examples\: : -67,\: -14, \:34 \:etc.$