Question

The sum of two integers is 23. The larger is 22 less than twice the smaller. Find the two integers.

Answer 1

LET THE SMALLER INTEGER BE X.
THEREFORE LARGER INTEGER WILL BE (2X-22)
A/Q;
X +(2X-22) = 23
THEREFORE X=15
THEREFORE SMALLER INTEGER =15
AND LARGER INTEGER=(2*15)-22=8