the sum of two natural number is 28 and their product is 192 find the number
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=let the no. be X and Y
X+Y=28.
X=28-Y =======eqn 1
XY=192 ======eqn 2
eqn 1 in eqn2
(28-y) Y=192
28Y- ysquare= 192
solving the quadratic eqn we get y
X+Y=28.
X=28-Y =======eqn 1
XY=192 ======eqn 2
eqn 1 in eqn2
(28-y) Y=192
28Y- ysquare= 192
solving the quadratic eqn we get y
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