The sum of two natural number is 8 determine the number if the sum of their reciprocal is 8/5?
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Let x and y are two natural no
Then x +y=8
Then 1÷x +1÷y=8÷5
Then y +x =8xy ÷5
Then 8 =8xy ÷5
40=8xy Then xy=5
Then x+y =8
xy=5
Then x=8 -Y
put value (8-y)(y)=5
8y-y^2-5
-y^2+8y-5 divided by -1
y^2-8y+5
solve that then values of x and y appears
Then x +y=8
Then 1÷x +1÷y=8÷5
Then y +x =8xy ÷5
Then 8 =8xy ÷5
40=8xy Then xy=5
Then x+y =8
xy=5
Then x=8 -Y
put value (8-y)(y)=5
8y-y^2-5
-y^2+8y-5 divided by -1
y^2-8y+5
solve that then values of x and y appears
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