the sum of two natural numbers is 12 and the sum of their squares is 74 find the numbers
Answers
Answered by
55
x+y = 12 [eq. 1]
x^2 + y^2 = 74
ATQ
(x+y)^2 = x^2 + 2xy + y^2
12^2 = 74 + 2xy
144 = 74 + 2xy
70 = 2xy
xy = 35.
NOW (x+y)^2- 4xy = (x-y)^2
so 144 - 140 = 4
so x-y = 2 [eq. 2]
solving 1 &2
x+y + x -y = 2+ 12
2x = 14
x = 7
and y = 5
HOPE IT HELPS!!...N PLZ FOLLOW IF U LYK MY ANSWER.
x^2 + y^2 = 74
ATQ
(x+y)^2 = x^2 + 2xy + y^2
12^2 = 74 + 2xy
144 = 74 + 2xy
70 = 2xy
xy = 35.
NOW (x+y)^2- 4xy = (x-y)^2
so 144 - 140 = 4
so x-y = 2 [eq. 2]
solving 1 &2
x+y + x -y = 2+ 12
2x = 14
x = 7
and y = 5
HOPE IT HELPS!!...N PLZ FOLLOW IF U LYK MY ANSWER.
Answered by
11
7 and 5 these are numbers
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