Question

The sum of two natural numbers is 121 if the sum of bigger number and four times the smaller is equal to or greater than 271, find all possible values of the smaller number

Answer 1

Step-by-step explanation:

Let the numbers be a and b.

So,

a + b = 121

a = 121 - b [Equation 1]

Again,

a + 4b >/= 271

121 - b +4b >/= 271

121 + 3b >/= 271

3b >/= 150

b >/= 50.

Therefore the value of b is either 50 or greater.