The sum of two no. Is 72. If one of the no. Is 6 more than the other,find the nos
Answers
Answered by
1
Let 1st number = x
2nd number = x+6
Sum of both number = x+(x+6) = 2x + 6
sum of both number = 72
according to the question -
2x+6=72
2x=72-6
2x=66
x=66÷2
x=33 answer
2nd number = x+6
Sum of both number = x+(x+6) = 2x + 6
sum of both number = 72
according to the question -
2x+6=72
2x=72-6
2x=66
x=66÷2
x=33 answer
Answered by
3
hello users ..
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we have given that:-
sum of two numbers = 72
such that:
one number is 6 more than other
solution:
let the first number = x
and
other will be = (x+6)
According to condition :
x + ( x+6) = 72
=> 2x + 6 =72
=> 2x = 72 - 6
=> x = 66/2 = 33
Hence;
the first number = 33
and
other number is = 33+6 = 39 Answer
`````````````````````````````````````````````````
# hope it helps :)
`````````````````````````````````
we have given that:-
sum of two numbers = 72
such that:
one number is 6 more than other
solution:
let the first number = x
and
other will be = (x+6)
According to condition :
x + ( x+6) = 72
=> 2x + 6 =72
=> 2x = 72 - 6
=> x = 66/2 = 33
Hence;
the first number = 33
and
other number is = 33+6 = 39 Answer
`````````````````````````````````````````````````
# hope it helps :)
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