the sum of two no. is 82, the large no. is exceeded three times the smaller no. by 6
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Answer:
required numbers are: 19, 63
Step-by-step explanation:
the large no. is exceeded three times the smaller number by 6
let smaller number= a
according to the given problem,
large number= 3a +6
the sum of two numbers = 82
a + 3a+ 6 = 82
4a = 82-6
4a = 76
a = 76/4
a = 19
3a+6 = 3×19+6
= 57+6
= 63
required numbers are: 19, 63
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