Question

the sum of two no. is 82, the large no. is exceeded three times the smaller no. by 6​

Answer 1

Answer:

required numbers are: 19, 63

Step-by-step explanation:

the large no. is exceeded three times the smaller number by 6

let smaller number= a

according to the given problem,

large number= 3a +6

the sum of two numbers = 82

a + 3a+ 6 = 82

4a = 82-6

4a = 76

a = 76/4

a = 19

3a+6 = 3×19+6

= 57+6

= 63

required numbers are: 19, 63