The sum of two no's is 11 Find the nos, if two times one of these nos exceeds three times the other no by 2
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Let us consider that the two numbers is a and b.
By the given conditions,
a + b = 11 ...(i)
2a = 3b + 2 ...(ii)
From (i), we get
a = 11 - b
Substituting a = 11 - b in (ii), we get
2(11 - b) = 3b + 2
⇒ 22 - 2b = 3b + 2
⇒ 3b + 2b = 22 - 2
⇒ 5b = 20
⇒ b = 4
∴ b = 4
From (i), we get
a + 4 = 11
⇒ a = 11 - 4
⇒ a = 7
∴ a = 7
Therefore, the two numbers are 7 and 4.
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Let us consider that the two numbers is a and b.
By the given conditions,
a + b = 11 ...(i)
2a = 3b + 2 ...(ii)
From (i), we get
a = 11 - b
Substituting a = 11 - b in (ii), we get
2(11 - b) = 3b + 2
⇒ 22 - 2b = 3b + 2
⇒ 3b + 2b = 22 - 2
⇒ 5b = 20
⇒ b = 4
∴ b = 4
From (i), we get
a + 4 = 11
⇒ a = 11 - 4
⇒ a = 7
∴ a = 7
Therefore, the two numbers are 7 and 4.
#MarkAsBrainliest
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