the sum of two number is 100 and the first number is 2 more than second number find the numbers
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Answered by
1
friend,
let the second number be x
first number be x+2
x+x+2=100
2x+2=100
2x=100-2
2x=98
x=98/2
x=49
hence,
second no is(x) =49
first no is(x+2)=49+2=51
have a nice day
let the second number be x
first number be x+2
x+x+2=100
2x+2=100
2x=100-2
2x=98
x=98/2
x=49
hence,
second no is(x) =49
first no is(x+2)=49+2=51
have a nice day
ravi0127:
thankyou brother
Answered by
3
Answer:
Step-by-step explanation:
Given that -
Sum of two numbers is 100 and the first number is 2 more than second number.
Let the second number be x. Then, first number = (x + 2).
According to the question;
x + (x + 2) = 100
⇒ x + x + 2 = 100
⇒ 2x + 2 = 100
⇒ 2x = 100 - 2
⇒ 2x = 98
⇒ x =
⇒ x = 49
Therefore, the numbers are:
- First number = 49
- Second number = 49 + 2 = 51
Hence, the numbers are 49 and 51.
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