the sum of two number is 203 and their differences is 10 find the number
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let the first number be x
let the second number be y
then
x+y=203-----------1 equation
x-y=10---------------2 equation
add the the equation 1 and 2
so
x+y=203
x-y+10
2x=213
then x= 213/2=106.5
in the equation 1 substitute x value
106.5+y=203
y=97.5
Answered by
0
x+y=203 (equation 1) and x_y= 10 (eq2) adding ( equation 1and 2) we get 2y=193 and y= 96.50 putting y= 96.50 in eq 1 we get the value of x = 106.50
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