Question

the sum of two number is 2346 one of them is twice the other. find them

Answer 1

$<h1>Answer :-</h1>$

Let a no. be x.

Other no. = 2x

$<b><u>According to Question :-</b></u>$

x + 2x = 2346

3x = 2346

x = $\dfrac{2346}{3}$

x = 782

So , one no. is 782.

Other no. = 2 × 782 = 1564

$<h1>Thanks !!$

Answer 2

$\huge{\pink{\boxed{\purple{\boxed{\orange{\textsf{Solution}}}}}}}$


Consider one number as X

=> X + 2X = 2346

=> 3X = 2346

=> X = 2346 ÷ 3

$\small{\green{\boxed{\green{\boxed{\red{\textsf{=> X = 782 }}}}}}}$


Second number = 2X

=> 2 × 782

$\small{\green{\boxed{\green{\boxed{\red{\textsf{=> 1564 }}}}}}}$

verification

=> 1564 + 782

=> 2346

Therefore

=> First number = 782

=> Second Number = 1564