Question

write the coordinates of the vertices of a square whose each side is 5 units, one vertex at (2,1) and all the vertices lie in the same quadrants

Answer 1

The coordinates of all the vertices are (2,1) (7,1) (7,6) (2,6)

Answer 2

Answer:

Other Coordinates of the vertices of the square are ( 7 , 1 ) , ( 2 , 6  ) and ( 7 , 6 )

Step-by-step explanation:

Given:

One of the Coordinate of vertices of the square = ( 2 , 1 )

Length of the side of the square = 5 units.

Square is in same quadrant that is in 1st Quadrant.

To find: Other Coordinates of the Square.

Square is in same quadrant that is in 1st Quadrant.

⇒ Other Coordinates are also in 1st Quadrant.

We know that All angles of the square are right angles.

So to find other coordinates we find point on the same line of the given point which is 5 unit perpendicularly away from given point.

When we take 2nd point on line y = 1

we get x-coordinate = 2 + 5 = 7

2nd coordinate = ( 7 , 1 )

Now if we take the 3rd point on line x = 2

then y-coordinate of 3rd point = 1 + 5 = 6

So, 3rd coordinate = ( 2 , 6 )

For the final point take line of 3rd quadrant y = 6

So the 4th point = ( 2 + 5 , 6 ) = ( 7 , 6 )

Figure is attached.

Therefore, Other Coordinates of the vertices of the square are ( 7 , 1 ) , ( 2 , 6  ) and ( 7 , 6 )