The sum of two number is 36 and one number exceeds another by 8 find the numbers
Answers
Answered by
0
Answer:
X+X+8=36
2x+8=36
2x=28
X=14
one number is 14 another is 22
Answered by
2
Step-by-step explanation:
let
x = 1st number
y=2nd second number
x+y = 36;
x-y = 8
_______
2x = 44
x=44÷2
{x =22}
put x value
x+y =36
22+y=36
y=36-22
{y=14}
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