Math, asked by plzanswermyquestion, 11 months ago

The sum of two number is 4000. If 15% of one number is equal to 25% of the other. Find both numbers.

a) 1000, 3000
b) 2400, 1600
c) 2500, 1500
d) 1200, 2800

Answers

Answered by sandipvadnerkar21
1

Answer:

c) 2500, 1500

Step-by-step explanation:

let the 2 given nos. be 'x' and 'y' respectively

according to first condition

x + y = 4000 ......( 1 )

according to second condition

15x / 100 = 25y / 100

= 15x = 25y ..... as hundreds gets cancelled

= 3x = 5y ...... after simplification

= 3x - 5y = 0 ......( 2 )

comparing both the equations

x + y = 4000

3x - 5y = 0

Multiplying equation ( 1 ) by 5

= 5x + 5y = 20000 ......( 3 )

comparing equation ( 2 ) and ( 3 )

= 5x + 5y = 20000

= 3x - 5y = 0

adding equation ( 2 ) and ( 3 )

= 5x + 5y = 20000

= 3x - 5y = 0

----------------------------

= 8x = 20000

x = 20000 / 8

x = 2500

putting x = 2500 in equation ( 1 )

x + y = 4000

2500 + y = 4000

y = 4000 - 2500

y = 1500

therefore x = 2500 & y = 1500

Answered by itzshrutiBasrani
0

Hey Buddy ❤❣

Answer

Let x and y be the two numbers.

First equation:

x+y=4000

Second equation (remember 15% of a number means .15 times the number):

.15x=.25y

Isolate y in the first equation:

x+y=4000

y=4000−x

Substitute this into the second equation:

.15x=.25(4000−x)

Distribute and solve for x:

.15x=1000−.25x

.4x=1000

x=2500

Substitute this into first equation written in terms of y:

y=4000−x

y=4000−(2500)

y=1500

Hope it helps you

Mark it as Brainliest Answer

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