The sum of two number is 55 and one of them is 4 times the other. Find the number?
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Answered by
3
Let the first no.= x
Let the second no.= 4x
A.T.Q.
4x + x = 55
5x = 55
x = 55÷5
x = 11
First no.=11
Second no.=11×4
=44
No.=44+11
=55
r9413119236:
Let the two numbers be x and y respectively.
Let the two numbers be x and y respectively. A.T.Q. x+y=55 -(1) 4x+y=55 -(2) By elimination method Multiply 4 in eq.(1) and subtract eq(2) from (1) 4x+4y=220 4x+y=55 --3y=165 y=55 Puty=55 in eq.(1) ,we get x=0 Two numbers are 0 and 55
Answered by
2
Let the first no. be x
if the second no. is four times x then
x + 4x = 55
5x= 55
x= 55/5
x= 11
therefore,
the first no. = 11
the second no. = 4x= 11x4= 44
therefore, the first no is 11 and the second no. is 44 because 11+ 44= 55.
hope it helps!
if the second no. is four times x then
x + 4x = 55
5x= 55
x= 55/5
x= 11
therefore,
the first no. = 11
the second no. = 4x= 11x4= 44
therefore, the first no is 11 and the second no. is 44 because 11+ 44= 55.
hope it helps!
Great d
Keep it up
thanks
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