Question

the sum of two number is 58 the greater number exceeds twice the smaller number by 1 find the number ​

Answer 1

SOLUTION:

let the first no. be x

let the second no. that exceeds 2x

x+2x=58

3x=58

x=58÷3

Answer. 19.333....

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Answer 2

Let the greater number be x and the smaller number be y

therefore from first condition we get,

x+y=58..... (1)

from second condition,

x=2y+1

x-2y=1........... (2)

multiplying equation one by 2 we get

2x-2y=116......(3)

adding equations one and three we get,

x=39

by substituting the value of x in equation one we get, y=19

therefore the greater number is 39 and the smaller number is 19