Question

The sum of two number is 72. if one of the number is 6 more than the other, find the numbers

Answer 1

let 1number =x
therefore 2 number= x+6

x+6+x= 72
2x+6=72
2x=72-6
2x=66
x=66÷2
x= 33

1 number=33
2 number=33+6=39

Answer 2

Let the first number be 'x'
Then, second number= 72 - x

let x > 72-x

Also, x - (72 - x) = 6

On solving ,
2x - 72 = 6
x = 78 / 2
i.e. x = 39

Hence , the first no. = 39
and second no. = 72 - 39 = 33

Hope it helps mate!