the sum of two number is 80 and the greater number exceed twice the smallet by 11 find the number
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Answer:
the number is 41
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Answered by
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Answer:
smaller no.=X=23
greater no.=2x+11=2*23+11=46+11=57
Step-by-step explanation:
sum=80
let the smaller no.=X
so the greater no.=2x+11
NOW A.T.Q
X+2x+11=80
3x=80-11
3x=69
X=69/3
X=23
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