# The sum of two number is2450, if 6% of a one number is equal to 8% of the other number, then the first number is

## Answers

Answered by

4

Hi

here is your Answer

one number be X

then 6% of X

= 6x/100

= 3x/50

&

second number be y

then 8% of y

= 8y/100

= 2y/25

and

sum of numbers

X+y = 2450............(1)

now

3x/50 = 2y/25

X = 2y×50/25×3

X = 4y/3

put the Value of X in equation 1

4y/3 +y = 2450

7y/3 = 2450

y = 2450×3/7

y = 350×3

y = 1050

X = 2450- 1050

X = 1400

Hence X = 1400, y = 1050 Ans

Hope it's helpful ✌✌✌

here is your Answer

one number be X

then 6% of X

= 6x/100

= 3x/50

&

second number be y

then 8% of y

= 8y/100

= 2y/25

and

sum of numbers

X+y = 2450............(1)

now

3x/50 = 2y/25

X = 2y×50/25×3

X = 4y/3

put the Value of X in equation 1

4y/3 +y = 2450

7y/3 = 2450

y = 2450×3/7

y = 350×3

y = 1050

X = 2450- 1050

X = 1400

Hence X = 1400, y = 1050 Ans

Hope it's helpful ✌✌✌

Answered by

0

**Answer:**

oo op bro but long method

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