The sum of two numbers a and b is 15 and the sum of their reciprocal is 3/10 find the no.
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Numbers are a and b.
A.t.q,
a + b = 15
b = 15 - a ------(i)
Given that : 1/a + 1/b = 3/10
Putting value of b :
1/a + 1/15-a = 3/10
15 - a + a / 15a - a² = 3/10
15 = 45a - 3a² / 10
150 = 45a - 3a²
3a² - 45a + 150 = 0
3a² - 30a - 15a + 150 = 0
3a ( a - 10 ) - 15 ( a - 10 )
( 3a - 15 ) ( a - 10 )
3a = 15 or a = 10
a = 5
Case : a = 5
a + b = 15
5 + b = 15
b = 10
Numbers are 5 and 10.
Case : a = 10
a + b = 15
10 + b = 15
b = 15 - 10
b = 5
Numbers are 5 and 10.
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