Question

The sum of two numbers I 38 when 8 added to twice one of the numbers the result is 5 times other the other number find the number

Answer 1

Step-by-step explanation:

F=first number; S=second number

.

F+S=38

S=38-F . Use this to substitute for S below.

.

2F+8=5S . Substitute for S from above.

2F+8=5(38-F)

2F+8=190-5F

7F=182

F=26

ANSWER 1: The first number is 26.

.

S=38-F=38-26=12

ANSWER 2: The second number is 12.

.

CHECK:

2F+8=5S

2(26)+8=5(12)

52+8=60

60=60

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Answer 2

Question:-

The sum of two numbers is 38 when 8 added to twice one of the numbers the result is 5 times other the other number find the number.

Solution:-

Given :-

a) The sum of two numbers is 38

b) 8 added to twice one of the numbers, the result is 5 times the other number

let, two numbers be x and y

by question

=> x + y = 38 ...... ( 1 )

=> 2x + 8 = 5y ...... ( 2 )

From ( 1 )

=> x = 38 - y ...... ( 3 )

now put, value of x in equation ( 2 ).

=> 2x + 8 = 5y

=> 2( 38 - y ) + 8 = 5y

=> 76 - 2y + 8 = 5y

=> 84 - 2y = 5y

=> - 2y - 5y = - 84

=> - 7y = - 84

=> 7y = 84

=> y = 84/7

=> y = 12

put value of y in equation ( 1 )

=> x + y = 38

=> x + 12 = 38

=> x = 38 - 12

=> x = 26

Hence two numbers are

x = 26 and y = 12.

i hope it helps you.