The sum of two numbers is 100 and their difference is 37. the difference of their squares is
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Answered by
3
let the two numbers x and y
x+y=100.......1
x-y=37.........2
from eq 1 we get x=100-y
from eq 2 we get x=37+y
on comparing
37+y=100-y
100-37=2y
63=2y
31.5=y
x-y=37
x=37+y
x=37+31.5
x=68.5
x+y=100
68.5+31.5=100
100=100
hence prooved
x+y=100.......1
x-y=37.........2
from eq 1 we get x=100-y
from eq 2 we get x=37+y
on comparing
37+y=100-y
100-37=2y
63=2y
31.5=y
x-y=37
x=37+y
x=37+31.5
x=68.5
x+y=100
68.5+31.5=100
100=100
hence prooved
Answered by
3
Answer:
Let x = the larger number
Let y = the smaller number
x+y = 100
x-y = 37 Add these two equations together.
2x = 137
x = 137/2
y = 100 - x
y = 100 - 137/2
y = 63/2
(137/2)2 - (63/2)2 = 3700
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